Created
May 21, 2020 12:31
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SQL same table join and find difference in days
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| SELECT | |
| renewals.start_date AS UUS_POLIIS_start_date | |
| ,policies.end_date AS EELMINE_POOLIIS_end_date | |
| ,renewals.id AS UUS_POLIIS_id | |
| ,policies.id AS EELMINE_POOLIIS | |
| ,DATEDIFF( renewals.start_date , policies.end_date ) AS DATE_DIFF | |
| FROM | |
| policies | |
| LEFT JOIN offering_policy ON offering_policy.policy_id = policies.id | |
| LEFT JOIN offerings ON offerings.id = offering_policy.offering_id | |
| /*MAGIC TRICK - JOIN SAME TABLE*/ | |
| /*JOIN samatabel AS ALIAS*/ | |
| /*ALIAS ON ALIAS.id = samatatabel.tulp */ | |
| LEFT JOIN policies AS renewals ON renewals.id = policies.renew_id | |
| WHERE | |
| policies.insurance_type_id = 6 | |
| AND policies.start_date >= "2019-01-31" | |
| AND policies.start_date <= "2019-12-31" | |
| AND policies.renew_id != 0 | |
| AND SUBSTRING(offerings.metadata, LOCATE("vehicle_year", offerings.metadata) +21, 4) != 2019 | |
| AND DATEDIFF( renewals.start_date , policies.end_date ) > 1 |
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