Last active
March 25, 2018 16:07
-
-
Save LeReverandNox/da9b0f0fd8dac9095fb547a5604f11c4 to your computer and use it in GitHub Desktop.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| digits = { | |
| 1: "one", | |
| 2: "two", | |
| 3: "three", | |
| 4: "four", | |
| 5: "five", | |
| 6: "six", | |
| 7: "seven", | |
| 8: "eight", | |
| 9: "nine", | |
| } | |
| tenthies = { | |
| 10: "ten", | |
| 11: "eleven", | |
| 12: "twelve", | |
| 13: "thirteen", | |
| 14: "fourteen", | |
| 15: "fifteen", | |
| 16: "sixteen", | |
| 17: "seventeen", | |
| 18: "eighteen", | |
| 19: "nineteen" | |
| } | |
| tens = { | |
| 2: "twenty", | |
| 3: "thirty", | |
| 4: "forty", | |
| 5: "fifty", | |
| 6: "sixty", | |
| 7: "seventy", | |
| 8: "eighty", | |
| 9: "ninety" | |
| } | |
| scale_words = [ | |
| "", | |
| "thousand", | |
| "million", | |
| "billion" | |
| ] | |
| def deal_with_group(number): | |
| elements = [] | |
| number_elements = [int(n) for n in str(number)] | |
| if number < 10: | |
| elements.append(digits[number]) | |
| elif number >= 10 and number < 20: | |
| elements.append(tenthies[number]) | |
| elif number >= 20 and number < 100: | |
| elements.append(tens[number_elements[0]] + (("-" + digits[number_elements[1]]) if number_elements[1] else '')) | |
| else: | |
| elements.append(digits[number_elements[0]] + " hundred" + ((" and " + deal_with_group(int(''.join([str(n) for n in number_elements[1:]])))) if number_elements[1] or number_elements[2] else '')) | |
| return ' '.join(elements) | |
| def say(number): | |
| if number < 0 or number > 10e11-1: | |
| raise ValueError("The given number is incorrect.") | |
| if number == 0: | |
| return "zero" | |
| number_string = str(int(number)) | |
| number_length = len(number_string) | |
| number_groups = [int(number_string[::-1][i:i+3][::-1]) for i in range(0, number_length, 3)] | |
| answer_elements = [] | |
| for i, group in enumerate(number_groups): | |
| if group == 0: | |
| continue | |
| answer_elements.append(scale_words[i]) | |
| answer_elements.append(deal_with_group(group)) | |
| if i == 0 and len(number_groups) > 1 and not number_groups[i+1]: | |
| answer_elements.append('and') | |
| return ' '.join(answer_elements[::-1]).strip() |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment