MolarFox · June 16, 2022 04:18
diff --git a/challenge.md b/challenge.md
diff --git a/molar_golf_solve_1.py b/molar_golf_solve_1.py
 def format_num(x: int) -> str:
  s = str(x)[::-1]
  return ''.join(
    c+(',' if (i+1)%3 == 0 else '') for i, c in enumerate(s)
  )[::-1].lstrip(',')
diff --git a/molar_golf_solve_2.py b/molar_golf_solve_2.py
 def format_num(x: int) -> str:
  return ''.join(
    c+(',' if (i+1)%3 == 0 else '') for i, c in enumerate(str(x)[::-1])
  )[::-1].lstrip(',')
diff --git a/molar_golf_solve_3.py b/molar_golf_solve_3.py
 def format_num(x: int) -> str:
  return ''.join(
    c+','*(not (i+1)%3) for i, c in enumerate(str(x)[::-1])
  )[::-1].lstrip(',')
diff --git a/molar_golf_solve_final.py b/molar_golf_solve_final.py
 format_num = lambda x: ''.join(c+','*(not (i+1)%3) for i, c in enumerate(str(x)[::-1]))[::-1].lstrip(',')
diff --git a/molar_solve_writeup.py b/molar_solve_writeup.py
 def format_num(x: int) -> str:
  s = str(x)   # int to string
  s = s[::-1]  # reverse string
  
  out_str = ""                # Accumulator for our output string
  for i, c in enumerate(s):   # Iterate reversed string by char (c) and char index (i)
    append_str = c              # Local var for next string(s) to append to the accumulator
    
    if not (i+1)%3:             # Congruent to `if (i+1)%3 == 0` - modulo index to determine when 3n chars have been traversed
      append_str += ','           # char then comma (since string construction is backwards) on every 3rd char
    
    out_str += append_str
    
  out_str = out_str[::-1]       # Reverse the constructed string, so it's now in the correct order
  out_str = out_str.lstrip(',') # If the digital length of input x is any 3n, unnecessary leading comma will be present - strip it
  
  return out_str  # :3
	def format_num(x: int) -> str:
	s = str(x)[::-1]
	return ''.join(
	c+(',' if (i+1)%3 == 0 else '') for i, c in enumerate(s)
	)[::-1].lstrip(',')
	def format_num(x: int) -> str:
	return ''.join(
	c+','*(not (i+1)%3) for i, c in enumerate(str(x)[::-1])
	)[::-1].lstrip(',')
	def format_num(x: int) -> str:
	s = str(x) # int to string
	s = s[::-1] # reverse string

	out_str = "" # Accumulator for our output string
	for i, c in enumerate(s): # Iterate reversed string by char (c) and char index (i)
	append_str = c # Local var for next string(s) to append to the accumulator

	if not (i+1)%3: # Congruent to `if (i+1)%3 == 0` - modulo index to determine when 3n chars have been traversed
	append_str += ',' # char then comma (since string construction is backwards) on every 3rd char

	out_str += append_str

	out_str = out_str[::-1] # Reverse the constructed string, so it's now in the correct order
	out_str = out_str.lstrip(',') # If the digital length of input x is any 3n, unnecessary leading comma will be present - strip it

	return out_str # :3