Classic binary search problem
-
Time complexity:
$$O(log\ n)$$ -
Space complexity:
$$O(1)$$
class Solution:
def search(self, nums: List[int], target: int) -> int:
low, high = 0, len(nums) - 1
while (low <= high):
mid = (low + high) // 2
if nums[mid] == target:
return mid
elif nums[mid] > target:
high = mid - 1
else:
low = mid + 1
return -1