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johnstew/digitalroot.js

Created April 3, 2013 14:32
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JS Digital Root
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digitalroot.js
function root(num){
var total = 0;
if(num.toString().length == 1){
var iNum = parseInt(num);
return iNum;
}else{
num.toString().split("").forEach( function(value){
var iValue = parseInt(value);
return total += iValue;
});
return root(total);
}
}
@nick3499
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nick3499 commented Jan 28, 2019 •
edited
Loading

came across something in a Python coding challenge. If n == 0 then that equation will return 9

def digital_root(n):
    if n == 0:
        return 0
    else:
        return (n-1) % 9 + 1
print(digital_root(0), 0)
print(digital_root(16), 7)

also in Ruby...

def digital_root(n)
  if n === 0
    return 0
  else
    return (n-1) % 9 + 1
  end
end

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ghost commented Oct 26, 2022

function digitalRoot(n) {
return n % 9;
}
that's it

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