All the programs below implement these steps:
- Generate a list of 1-8, not including 8: [1, 2, 3, 4, 5, 6, 7]
- Filter that list to even values: [2, 4, 6]
- Return each value N repeated N times: [2, 2, 4, 4, 4, 4, 6, 6, 6, 6, 6, 6]
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October 3, 2023 19:01
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Example of chaining functions
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| from pydash import py_ | |
| def is_even(n): | |
| return n % 2 == 0 | |
| def repeat(n, times): | |
| return [n] * times | |
| def concat(list_a, list_b): | |
| return [*list_a, *list_b] | |
| def computed(): | |
| return ( | |
| py_(py_.range(1, 8)) | |
| .filter(is_even) | |
| .map(lambda n: repeat(n, n)) | |
| .reduce(concat, []) | |
| .value() | |
| ) | |
| print(computed()) | |
| # > python compute-with-python.py | |
| # [2, 2, 4, 4, 4, 4, 6, 6, 6, 6, 6, 6] |
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| from functools import reduce | |
| def is_even(n): | |
| return n % 2 == 0 | |
| def repeat(n, times): | |
| return [n] * times | |
| def concat(list_a, list_b): | |
| return [*list_a, *list_b] | |
| def computed(): | |
| numbers = range(1, 8) | |
| evens = filter(is_even, numbers) | |
| repeats = map(lambda n: repeat(n, n), evens) | |
| values = reduce(concat, repeats, []) | |
| return values | |
| print(computed()) | |
| # > python compute.py | |
| # [2, 2, 4, 4, 4, 4, 6, 6, 6, 6, 6, 6] |
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