sparksp/try_to_i.rb

Created February 23, 2016 15:59

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Try to cast to an integer

Raw

try_to_i.rb

	def try_to_i(string)
	if string.to_i.to_s == string
	string.to_i
	else
	string
	end
	end

c0nspiracy commented Feb 23, 2016

Since we're only concerned with positive integers:

def column_letter_or_index(string)
  /\A\d+\z/ === string ? string.to_i : string
end

You'd probably want to .strip the string first to prevent accidental whitespace creeping in from the command-line.

Author

sparksp commented Feb 24, 2016

@c0nspiracy I think you have to try really hard for white space to creep in from the command-line... e.g., by quoting your input.

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